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Question

The ratio of surface areas of 1 cube of volume 64 cm3 and 64 cubes of volume 1 cm3 is:


A

1: 1

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B

1: 2

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C

1: 3

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D

1: 4

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Solution

The correct option is D (1:4)

Let us name the cube of volume 64 cm3 as cube A and the cube with volume 1 cm3 as cube B.

Length of side of cube A =364=4 cm

Surface area of cube A =6×(4)2=6×16=96 cm2

Length of side of cube B =1 cm

Surface area of a cube of side 1 cm =6 cm2

Therefore, surface area of 64 such cubes =64×6=384 cm2

Required ratio of surface areas =96:384

=1:4


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