The ratio of surface areas or 1 cube of volume 64 cubic cm and 64 cubes of volume 1 cubic cm is ________________
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Solution

Volume of larger cube= 64 $c m^{3}$
let the side of larger cube be A
$A^{3} = 64 c m^{3}$
A= 4 cm
Surface area = 6 $A^{2}$ =6( $4^{2}$ )= 6(16) =96 $c m^{2}$

Volume of smaller cube= 1 $c m^{3}$
let the side of smaller cube be a
$a^{3} = 1 c m^{3}$
a= 1 cm
Surface area = 6( $a^{2}$ )=6(1) =6 $c m^{2}$
Surface area of 64 smaller cubes = 64 x 6 =384 $c m^{2}$

Ratio = 96 / 384 = 1/4=1:4

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