Question

The ratio of the angular node of a $3s$ orbital to the spherical node of a $4p$ orbital is:

Answer 1

As we know,
Angular node $=l$ and spherical node $=(n-l-1)$.

For $3s,\ell =0$, angular node is $0$.

For $4p,l=1$, spherical node is $(4-1-1)=2$.

The ratio is $\frac{0}{2}=0$.