Question

The ratio of the area of a square to that of the square drawn on its diagonal is

• A. 1 : 1
• B. 1 : 2
• C. 1 : 3
• D. 1 : 4

Answer 1

The correct option is B 1 : 2

Let the side of square is x

Then side of diagonal=$\sqrt{(side{)}^2+(side{)}^2}=\sqrt{x^2+x^2}=\sqrt{2x^2}=\sqrt{2}x$

Then area of square(A)=$x^2$

And Then area of square on diagonal (D)=$(\sqrt{2}x{)}^2=2x^2$

Then area of square(A) : area of square on diagonal (D)=$x^2:2x^2=1:2$