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Question

The ratio of the coefficient of x2 to the coefficient of x10 in the expansion of (x5+43log3x3)10 is

A
4:7
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B
10:3
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C
3:10
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D
7:4
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Solution

The correct option is B 10:3
(x5+43log3x3)10=(x5+4x3)10

Tr+1= 10Cr(x5)10r(4x3)r = 10Cr(4)rx508rNow, 508r=2r=6& 508r=10r=5

Required ratio=10C64610C545=103

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