The ratio of the corresponding sides of the two similar triangles is $2 : 3$ and the area of the smaller triangle is $64 s q . c m$ . Find the area of larger triangle.

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Solution

For similar triangles, ratio of areas = ratio of square of corresponding sides
$\frac{A r . f i r s t t r i a n g l e}{A r . s e c o n d t r i a n g l e} = \frac{2^{2}}{3^{2}}$
$\frac{64}{A r . t r i a n g l e} = \frac{4}{9}$
Ar. of triangle $= \frac{9}{4} (64)$
Ar. of triangle $= 9 \times 16$
Ar. of triangle $= 144 s q . c m$

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The corresponding sides of two similar triangles are in the ratio of $2 : 3$ . If the area of the smaller triangle is $48 c m^{2}$ , find the area of the larger triangle.

Q. Question 10
Corresponding sides of two similar triangles are in the ratio of 2:3. If the area of the smaller triangles is 48

c m^{2}

, then find the area of the larger triangle.

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The ratio of the corresponding sides of the two similar triangles is 2:3 and the area of the smaller triangle is 64sq.cm. Find the area of larger triangle.

For similar triangles, ratio of areas = ratio of square of corresponding sidesAr. first triangleAr. second triangle=223264Ar.triangle=49Ar. of triangle =94(64)Ar. of triangle =9×16Ar. of triangle =144sq.cm

The ratio of the corresponding sides of the two similar triangles is $2 : 3$ and the area of the smaller triangle is $64 s q . c m$ . Find the area of larger triangle.