The ratio of the difference between number of hydrogens present in 'propane and propyne' and 'propane and propene' is:

1 : 2

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2 : 1

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3 : 2

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2 : 3

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Solution

The correct option is B 2 : 1
No. of hydrogen atoms in propane( $C H_{3} - C H_{2} - C H_{3}$ ) = 8

No. of hydrogen atoms in propene ( $C H_{3} - C H = C H_{2}$ ) = 6

No. of hydrogen atoms in propyne ( $C H_{3} - C \equiv C H$ ) = 4

The difference in no. of hydrogen atoms between propane and propyne = 8-4=4

The difference in no. of hydrogen atoms between propane and propene = 8-6=2

Therefore, the ratio $= 4 : 2 = 2 : 1$ .

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