Question

The ratio of the difference in energy of electron between the first and second Bohrs orbit to that between second and third Bohrs orbit is:

• A. $\frac{1}{3}$
• B. $\frac{27}{5}$
• C. $\frac{9}{4}$
• D. $\frac{4}{9}$

Answer 1

Answer: (B)

$\frac{27}{5}$

$\Delta E=R_H{Z}^2(\frac{1}{n_2^2}-\frac{1}{n_1^2})$
Ratio $=(E_2-E_1)/(E_3-E_2)=\left(\frac{3}{4}\right)/\left(\frac{5}{36}\right)=\frac{27}{5}$.