The ratio of the distances travelled by a body starting from rest and moving with uniform acceleration in the first, third and fifth seconds of its journey is:

1 : 3 : 5

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1 : 2 : 3

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1 : 4 : 9

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1 : 5 : 9

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Solution

The correct option is D $1 : 5 : 9$
Let $s_{n}$ be the distance travelled in nth sec
$s n = u + \frac{a}{2} (2 n - 1)$
$u = 0$ so
$s = \frac{a}{2} (2 n - 1)$
$s_{1} : s_{3} : s_{5} = (2 \times 1 - 1) : (2 \times 3 - 1) : (2 \times 5 - 1)$
$s_{1} : s_{3} : s_{5} = 1 : 5 : 9$

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The ratio of the distances travelled by a body starting from rest and moving with uniform acceleration in the first, third and fifth seconds of its journey is:

The correct option is D 1:5:9Let sn be the distance travelled in nth secsn=u+a2(2n−1)u=0 sos=a2(2n−1)s1:s3:s5=(2×1−1):(2×3−1):(2×5−1)s1:s3:s5=1:5:9

The correct option is D $1 : 5 : 9$
Let $s_{n}$ be the distance travelled in nth sec
$s n = u + \frac{a}{2} (2 n - 1)$
$u = 0$ so
$s = \frac{a}{2} (2 n - 1)$
$s_{1} : s_{3} : s_{5} = (2 \times 1 - 1) : (2 \times 3 - 1) : (2 \times 5 - 1)$
$s_{1} : s_{3} : s_{5} = 1 : 5 : 9$