The ratio of the forces between two small spheres with constant charge (a) in air (b) in a medium of dielectric constant K is

1 : K

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K : 1

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1 : K^{2}

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K^{2} : 1

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Solution

The correct option is B K : 1
$F_{a} = \frac{q_{1} q_{2}}{4 π ε_{0} r^{2}}, F_{b} = \frac{q_{1} q_{2}}{K 4 π ε_{0} r^{2}}, \Rightarrow F_{a} : F_{b} = K : 1$

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