wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The ratio of the kinetic energy Ek and potential energy of a particle executing SHM, at a distance x from mean position will be

A
x2x2a2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x2a2x2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x2a2x2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a2x2x2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D a2x2x2

KEPE=0.5mv20.5kx2

=ma2ω2cos2ωtmω2.a2.sin2ωt=cos2ωtsin2ωt
=1sin2ωtsin2ωt
Now, sinωt=x/a
Thus, KEPE=1x2/a2x2/a2=a2x2x2


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Energy in SHM
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon