The ratio of the kinetic energy of a particle executing SHM at its mean position to its potential energy at extreme position is

= 1

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= 1 / g

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> 1

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< 1

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Solution

The correct option is B $= 1$
At mean, KE is maximum, equal to TE and PE=0.
At extreme, PE is maximum = TE and KE=0.
Since TE is constant, thus they both are equal, and hence ratio is 1.

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The ratio of the kinetic energy of a particle executing SHM at its mean position to its potential energy at extreme position is

The correct option is B =1At mean, KE is maximum, equal to TE and PE=0.At extreme, PE is maximum = TE and KE=0.Since TE is constant, thus they both are equal, and hence ratio is 1.

The correct option is B $= 1$
At mean, KE is maximum, equal to TE and PE=0.
At extreme, PE is maximum = TE and KE=0.
Since TE is constant, thus they both are equal, and hence ratio is 1.