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Standard IX

Physics

Heat Transfer

The ratio of ...

Question

The ratio of the latent heat of steam to latent heat of ice

4/9

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9/4

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4/27

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27/4

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Solution

The correct option is C 27/4
The latent heat of vaporization of water is 540 cal/g and latent heat of fusion of ice is 80 cal/g. Thus the ratio is $\frac{540}{80} = \frac{27}{4}$

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Similar questions

Q. Latent heat of vapourisation of water or latent heat of steam =___________ .

Q. 1 g of a steam at

100^{_{-}^{0}} C

melt how much ice at

0^{_{-}^{0}} C

? (Latent heat of ice = 80 cal/gm and latent heat of steam = 540 cal/gm)-

Q. Ice at

0^{\circ} C

is added to

1 g

of steam at

100^{\circ} C

. For

x g

of ice added, the temperature of steam reduces to

0^{\circ} C

. Find the value of

x

.
(Latent heat of ice

= 80 cal/g

and latent heat of steam

= 540 cal/g

. Also, specific heat of water

= 1 cal/ kg K

)

Q. The amount of heat required to convert

1 g

of ice at

- 10^{o}

C into steam at

100^{o}

C is (specific heat of ice

= 0.5

cal/g/

^{o}

C, latent heat of ice

= 80

cal/g, latent heat of steam

= 540

cal/g)

Ratio of heat energy required to change in states of $100 g$ of water at $100^{\circ} C$ to steam to $540 g$ of ice to water respectively is $5 : y$ then $y$ = ___

Take latent heat of fusion $80 c a l / g m$ and latent heat of vaporization as $540 c a l / g m$

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The ratio of the latent heat of steam to latent heat of ice

The correct option is C 27/4The latent heat of vaporization of water is 540 cal/g and latent heat of fusion of ice is 80 cal/g. Thus the ratio is 54080=274

The correct option is C 27/4
The latent heat of vaporization of water is 540 cal/g and latent heat of fusion of ice is 80 cal/g. Thus the ratio is $\frac{540}{80} = \frac{27}{4}$