The ratio of the magnetic field at the centre of a current carrying circular wire and the magnetic field at the centre of a square coil made from the same length of wire is
A
π2√2
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B
π4√2
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C
π24√2
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D
π28√2
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Solution
The correct option is Dπ28√2 Magnetic field at the centre of a circular coil BCircular=μ04π2πir=μ04π4π2iL[∵L=2πrandr=12π] Magnetic field at the centre of square coil BSquare=μ04π8√2ia=μ04π32√2iL[∵L=4aanda=L4] Hence, BCircularBSquare=mu04π4π2iLμ04π32√2iL=π28√2.