The ratio of the magnetic field at the centre of a current carrying coil of the radius a and at a distance 'a' from centre of the coil and perpendicular to the axis of coil is

\frac{1}{\sqrt{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{2 \sqrt{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 \sqrt{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B $2 \sqrt{2}$
$\frac{B_{c}}{B_{a}} = {(1 + \frac{c^{2}}{a^{2}})}^{3 / 2} = {(1 + \frac{a^{2}}{a^{2}})}^{3 / 2} = (1 + 1)^{3 / 2} = 2 \sqrt{2}$

Suggest Corrections

Similar questions

Q. Radius of a current carrying coil is

R

The ratio of magnetic field at a axial point which is

R

distance away from the centre of the coil to the magnetic field at the centre of the coil:

Q. The radius of a circular current carrying coil is

R

. At what distance from the centre of the coil on its axis, the intensity of magnetic field will be

\frac{1}{2 \sqrt{2}}

times that at the centre?

Q. A circular coil of radius

2 R

is carrying current

i

.The ratio of magnetic fields at the centre of the coil and at a point at a distance

6 R

from the centre of the coil on the axis of the coil is :

A circular current carrying coil has a radius R. The distance from the centre of the coil on the axis where the magnetic induction will be ${\frac{1}{8}}^{t h}$ to its value at the centre of the coil, is

Q. At what distance on the axis, from the centre of a circular current carrying coil of radius r, the magnetic field becomes 1/8th of the magnetic field at centre?

Join BYJU'S Learning Program

The ratio of the magnetic field at the centre of a current carrying coil of the radius a and at a distance 'a' from centre of the coil and perpendicular to the axis of coil is

The correct option is B 2√2BcBa=(1+c2a2)3/2=(1+a2a2)3/2=(1+1)3/2=2√2

The correct option is B $2 \sqrt{2}$
$\frac{B_{c}}{B_{a}} = {(1 + \frac{c^{2}}{a^{2}})}^{3 / 2} = {(1 + \frac{a^{2}}{a^{2}})}^{3 / 2} = (1 + 1)^{3 / 2} = 2 \sqrt{2}$