The ratio of the moment of inertia of circular ring & circular disc having the same mass & radii about an axis passing the $c . m$ & perpendicular to plane is

1 : 1

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2 : 1

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1 : 2

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4 : 1

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Solution

The correct option is C $2 : 1$
Moment of inertia $(M . I)$ of circular ring $I_{1} = m r^{2}$
Moment of inertia $(M . I)$ of circular disc $I_{2} = \frac{1}{2} m r^{2}$
$\Rightarrow \frac{I_{1}}{I_{2}} = \frac{2}{1}$

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The ratio of the moment of inertia of circular ring & circular disc having the same mass & radii about an axis passing the c.m & perpendicular to plane is

The correct option is C 2:1Moment of inertia (M.I) of circular ring I1=mr2Moment of inertia (M.I) of circular disc I2=12mr2⇒I1I2=21

The ratio of the moment of inertia of circular ring & circular disc having the same mass & radii about an axis passing the $c . m$ & perpendicular to plane is

The correct option is C $2 : 1$
Moment of inertia $(M . I)$ of circular ring $I_{1} = m r^{2}$
Moment of inertia $(M . I)$ of circular disc $I_{2} = \frac{1}{2} m r^{2}$
$\Rightarrow \frac{I_{1}}{I_{2}} = \frac{2}{1}$