Question

The ratio of the neutrons present in nitrogen atom and a silicon atom is:

(Mass number of nitrogen and silicon is 14 and 28 respectively)

• A. 7 : 3
• B. 3 : 7
• C. 1 : 2
• D. 2 : 1

Answer 1

Answer: (C)

1 : 2

For nitrogen; atomic number = 7 and mass number = 14

$\therefore$ Number of neutrons $=14-7=7$
For silicon; atomic number = 14 and mass number = 28

$\therefore$ number of neutrons $=28-14=14$
$\therefore$ Ratio of number of neutrons in nitrogen and silicon $=7:14=1:2$