The ratio of the rth term and the (r+1)th term in the expansion of (1+x)n is
A
r(n−r+1)x
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B
1(n−r+1)x
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C
r(n−r+1)
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D
(n−r+1)xr
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Solution
The correct option is Cr(n−r+1)x Tthr term =nCr−1xr−1 ...(i) And Tr+1th term =nCrxr ...(ii) Therefore, TrTr+1 =nCr−1xr−1nCrxr =nCr−1nCrx =r(n−(r−1))x =r(n−r+1)x