The ratio of the radii of the first three Bohr orbits is:

1 : 0.5 : 0.33

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1 : 2 : 3

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1 : 4 : 9

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1 : 8 : 27

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Solution

The correct option is C $1 : 4 : 9$
$r_{n} = r_{0} \times \frac{n^{2}}{Z}$ , here $Z = 1$
$r_{1} = r_{0}$
$r_{1} = 4 r_{0}$
$r_{3} = 9 r_{0}$
Ratio $= r_{1} : r_{2} : r_{3} = 1 : 4 : 9$ .

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