Question

The ratio of the radii of the nuclei ${}_{13}A{l}^{27}$ and ${}_{52}T{e}^{125}$ is approximately.

• A. $3:5$
• B. $27:125$
• C. $13:52$
• D. $14:73$

Answer 1

The correct option is A $3:5$

A. 3:5

Atomic number of Al= 13

Radius of the nucleus, $R=R_o(A{)}^{\frac{1}{3}}$

R= 1.3$(13{)}^{\frac{1}{3}}=3fm$

Atomic number of Te= 52

Radius of the nucleus, $R=R_o(A{)}^{\frac{1}{3}}$

R= 1.3$(52{)}^{\frac{1}{3}}=5fm$

Ratio of radi of the nuclei ${}_{13}A{l}^{127}$ and ${}_{52}T{e}^{125}$ is $3:5$