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Standard X

Chemistry

Bohr's Model of Atom

The ratio of ...

Question

The ratio of the radius of Bohr first orbit for the electron orbiting the hydrogen nucleus to that of the electron orbiting the deuterium nucleus (mass nearly twice that of nucleus) is approximately:

1 : 1

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1 : 2

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2 : 1

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1 : 4

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Solution

The correct option is A $1 : 1$
Expression for Bohr's radius is given by,
$r = \frac{n^{2} h^{2}}{4 π^{2} m k Z e^{2}}$ since $n = 1, Z = 1$ for both hydrogen & deuterium nucleus, the ratio of the radius is $1 : 1$ .

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The ratio of the radius of Bohr first orbit for the electron orbiting the hydrogen nucleus to that of the electron orbiting the deuterium nucleus (mass nearly twice that of nucleus) is approximately:

The correct option is A 1:1Expression for Bohr's radius is given by,r=n2h24π2mkZe2 since n=1,Z=1 for both hydrogen & deuterium nucleus, the ratio of the radius is 1:1 .

The correct option is A $1 : 1$
Expression for Bohr's radius is given by,
$r = \frac{n^{2} h^{2}}{4 π^{2} m k Z e^{2}}$ since $n = 1, Z = 1$ for both hydrogen & deuterium nucleus, the ratio of the radius is $1 : 1$ .