The ratio of the rates of diffusion of helium and methane under identical conditions of pressure and temperature is:

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Solution

The correct option is B 2
Grahams law:
Rate of diffusion or effusion of a gas at given conditions inversely proportional to the root of molecular mass & gas.
$r_{1} / r_{2} = \sqrt{M_{2} / M_{1}}$
$\frac{r_{H e}}{r_{C H_{4}}} = \sqrt{\frac{M_{C H_{4}}}{M_{H e}}} = \sqrt{\frac{16}{4}} = 2$

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The ratio of the rates of diffusion of helium and methane under identical conditions of pressure and temperature is:

The correct option is B 2Grahams law:Rate of diffusion or effusion of a gas at given conditions inversely proportional to the root of molecular mass & gas.r1/r2=√M2/M1rHerCH4=√MCH4MHe=√164=2

The correct option is B 2
Grahams law:
Rate of diffusion or effusion of a gas at given conditions inversely proportional to the root of molecular mass & gas.
$r_{1} / r_{2} = \sqrt{M_{2} / M_{1}}$
$\frac{r_{H e}}{r_{C H_{4}}} = \sqrt{\frac{M_{C H_{4}}}{M_{H e}}} = \sqrt{\frac{16}{4}} = 2$