The ratio of the sides AB - BC - AC is equal to- 5 - 13 - 12-12 - 13 - 5-5 - 12 - 13-13 - 5 - 12

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Exterior Angle Theorem

The ratio of ...

Question

The ratio of the sides AB : BC : AC is equal to

5 : 13 : 12

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12 : 13 : 5

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5 : 12 : 13

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13 : 5 : 12

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Verify each of the following :

(i) $\frac{3}{7} \times \frac{- 5}{9} = \frac{- 5}{9} \times \frac{3}{7}$

(ii) $\frac{- 8}{7} \times \frac{13}{9} = \frac{13}{9} \times \frac{- 8}{7}$

(iii) $\frac{- 12}{5} \times \frac{7}{- 36} = \frac{7}{- 36} \times \frac{- 12}{5}$

(iv) $- 8 \times \frac{- 13}{12} = \frac{- 13}{12} \times (- 8)$

Verify the following

(i) $\frac{- 12}{5} + \frac{2}{7} = \frac{2}{7} + \frac{- 12}{5}$

(ii) $\frac{- 5}{8} + \frac{- 9}{13} = \frac{- 9}{13} + \frac{- 5}{8}$

(iii) $3 + \frac{- 7}{12} = \frac{- 7}{12} + 3$

(iv) $\frac{2}{- 7} + \frac{12}{- 35} = \frac{12}{- 35} + \frac{2}{- 7}$

In figure, AC = 13 cm, BC = 12 cm, then sec θ equals :

Δ A B C, A B = 5, B C = 12

A C = 13

In given figure, AD = 4 cm, BD = 3 cm and BC = 12cm, then cot C =

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