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Question

The ratio of the sums of m and n terms of an A.P. is m2: n2. Show that the ratio of mth and nth term is (2m ā€“ 1): (2n ā€“ 1).

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Solution

Let a and b be the first term and the common difference of the A.P. respectively.

According to the given condition,

Putting m = 2m ā€“ 1 and n = 2n ā€“ 1 in (1), we obtain

From (2) and (3), we obtain

Thus, the given result is proved.


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