The ratio of the time taken by light to travel a distance of 100 m in air and water is
(Given $c = 3 \times 10^{8}$ m/s ; $μ_{a i r} = 1.0003$ ; $μ_{w a t e r} = \frac{4}{3}$ )

1 : 1.1

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0.7502 : 1

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1 : 1.4

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1 : 1.5

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Solution

The correct option is B $0.7502 : 1$
Time taken in air $= \frac{100}{c / μ_{a i r}} = \frac{100 μ_{a i r}}{C}$
Time taken in water $= \frac{100}{c / μ_{w a t e r}} = \frac{100 μ_{w a t e r}}{C}$
$\frac{t i m e t a k e n i n a i r}{t i m e t a k e n i n w a t e r} = \frac{100 μ_{a i r} / C}{100 μ_{w a t e r} / C}$
$= \frac{μ_{a i r}}{μ_{w a t e r}}$

$= \frac{1.0003}{4 / 3}$

$= \frac{3 \times 1.0003}{4}$

$= \frac{0.7502}{1}$

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The ratio of the time taken by light to travel a distance of 100 m in air and water is (Given c=3×108 m/s ; μair=1.0003; μwater=43)

The correct option is B 0.7502:1Time taken in air =100c/μair=100μairCTime taken in water =100c/μwater=100μwaterCtimetakeninairtimetakeninwater=100μair/C100μwater/C =μairμwater =1.00034/3 =3×1.00034 =0.75021

The ratio of the time taken by light to travel a distance of 100 m in air and water is
(Given $c = 3 \times 10^{8}$ m/s ; $μ_{a i r} = 1.0003$ ; $μ_{w a t e r} = \frac{4}{3}$ )