The ratio of the volume of a cube to that of a sphere which will fit inside the cube is

4 : π

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4 : 3 π

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6 : π

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2 : π

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Solution

The correct option is C $6 : π$
Let Radius of Sphere be r.
Then,Each side of Cube=2r.
ratio= $\frac{Volume of cube}{Volume of Sphere}$
$=> \frac{(2 r)^{3}}{\frac{4}{3} π \times r^{3}}$
$=> 6 : π$

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Similar questions

Q. The volume of a sphere is

\frac{4}{3} π r^{3} c . c .

What is the ratio of the volume of a cube to that of a sphere which will fit inside the cube?

Q. The volume of a sphere is

\frac{4}{3} π r^{3}

cubic units, then the ratio of the volume of a cube to that of a sphere which will fit inside the cube is:

If a sphere is inscribed in a cube, then the ratio of the volume of the sphere to the volume of the cube is
(a) $π : 2$
(b) $π : 3$
(c) $π : 4$
(d) $π : 6$

Q. A sphere and a cube have same surface area. Show that the ratio of the volume of sphere to that of cube is √6:√π.

Q. Question 9
If a sphere is inscribed in a cube, then the ratio of the volume of the cube to the volume of the sphere will be

6 : π

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The ratio of the volume of a cube to that of a sphere which will fit inside the cube is

The correct option is C 6:πLet Radius of Sphere be r.Then,Each side of Cube=2r.ratio=Volume of cubeVolume of Sphere=>(2r)343π×r3=>6:π

The correct option is C $6 : π$
Let Radius of Sphere be r.
Then,Each side of Cube=2r.
ratio= $\frac{Volume of cube}{Volume of Sphere}$
$=> \frac{(2 r)^{3}}{\frac{4}{3} π \times r^{3}}$
$=> 6 : π$