The ratio of the wave lengths of the first line in the Lyman series of the spetrum of Hydorgen atom and the first line in the Balmer series of the spectrum of $H e^{+}$ is

20/27

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Solution

The correct option is A
20/27

$\frac{λ_{2}}{λ_{1}} = \frac{{[\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}]}_{1}}{{[\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}]}_{2} \times 2^{2}}$

$\frac{λ_{2}}{λ_{1}} = \frac{\frac{5}{36} \times 4}{\frac{3}{4}} = \frac{20}{27}$

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The ratio of the wave lengths of the first line in the Lyman series of the spetrum of Hydorgen atom and the first line in the Balmer series of the spectrum of He+ is

The correct option is A 20/27 λ2λ1=[1n21−1n22]1[1n21−1n22]2×22 λ2λ1=536×434=2027

The ratio of the wave lengths of the first line in the Lyman series of the spetrum of Hydorgen atom and the first line in the Balmer series of the spectrum of $H e^{+}$ is

The correct option is A
20/27

$\frac{λ_{2}}{λ_{1}} = \frac{{[\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}]}_{1}}{{[\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}]}_{2} \times 2^{2}}$

$\frac{λ_{2}}{λ_{1}} = \frac{\frac{5}{36} \times 4}{\frac{3}{4}} = \frac{20}{27}$