Question

The ratio of the weight of a man in a stationary lift and when it is accelerating downward with uniform acceleration $a$ is $3:2$. The value of $a$ is (Acceleration due to gravity is $g$ )

• A. $\frac{3}{2}g$
• B. $\frac{g}{3}$
• C. $\frac{2}{3}g$
• D. $g$

Answer 1

The correct option is B $\frac{g}{3}$

Weight in stationary lift $N=mg$
Weight in lift moving down with uniform acceleration
$N^{\prime }=m(g-a)$
Given $\frac{N}{N^{\prime }}=\frac{3}{2}=\frac{g}{g-a}$
$\Rightarrow 3g-3a=2g$
$a=g/3$