Question

The ratio of the weights of Meenakshi to that of her friend Ankur is 13:15. Ankur now starts to exercise daily and loses 5 kg, and now the ratio of their weights is 13:14. How much does Ankur weigh now?

Answer 1

Concept: 1 Mark
Application: 1 Mark
Steps: 1 Mark
Solution: 1 Mark

Let x and y be the weight of Meenakshi and Ankur has respectively.

The ratio of the weights of Meenakshi to Ankur = 13:15

After exercising, ratio of the weights of Meenakshi to Ankur = x :( y-5) = 13:14

Comparing both $\frac{x}{y}$ = $\frac{13}{15}$ and $\frac{x}{y-5}$ = $\frac{13}{14}$ we get,

$\Rightarrow 13y=15x..............\left(i\right)$ and
$14x=13(y-5)$
$\Rightarrow 14x=13y-\mathrm{65............}\left(ii\right)$

Substituting the value of (i) in (ii) we get,
$\Rightarrow 14x=15x-65$.
$x=65$

Substitute the value of x in (i)
$\Rightarrow 13y=15\times 65$
$y=15\times 5=75$

But Ankur lost 5 kg

$\therefore$ Ankur's present weight is $(y-5)=(75-5)=70kg$