Question

The ratio of time constants during current growth and current decay of the circuit shown in figure is k:2, then k=___

Answer 1

During charging ${\tau }_{L_1}=\frac{L}{2R}$
and during discharging ${\tau }_{L_2}=\frac{L}{3R}$

$\therefore \frac{{\tau }_{L_1}}{{\tau }_{L_2}}=\frac{L/2R}{L/3R}=\frac{3}{2}$