The ratio of time period of three identical springs if they are first joined in parallel and then in series is (assume same mass is suspended from them)
A
1:3
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B
2:1
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C
2:3
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D
9:1
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Solution
The correct option is A1:3 Effective spring constant when connected in series, 1KS=1K+1K+1K⇒Ks=K3
In parallel, KP=K+K+K=3K
Time period in series Ts=2π√m(K3)=2π√3mK Time period in parallel TP=2π√m3K