The ratio of two frequencies of mechanical waves is 4:3 propagating in a medium. What will be:
The ratio of their time period?

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Solution

Step 1- Given data
$\frac{f_{1}}{f_{2}} = \frac{4}{3}$ where the wave velocity is v, frequency is f and T is the time period.
Step 2- Finding the ratio of time periods
As Formula used to find the frequency $f = \frac{1}{T}$
so $T = \frac{1}{f}$
so, $\frac{T_{1}}{T_{2}} = \frac{f_{2}}{f_{1}}$
$\frac{T_{1}}{T_{2}} = \frac{f_{2}}{f_{1}}$ = $\frac{3}{4}$ .
Final Answer- Thus, the ratio of their time periods is $3 : 4$ .

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The ratio of two frequencies of mechanical waves is 4:3 propagating in a medium. What will be:The ratio of their time period?

Step 1- Given dataf1f2=43 where the wave velocity is v, frequency is f and T is the time period.Step 2- Finding the ratio of time periodsAs Formula used to find the frequency f=1T so T=1fso, T1T2=f2f1T1T2=f2f1 =34.Final Answer- Thus, the ratio of their time periods is 3:4.

The ratio of two frequencies of mechanical waves is 4:3 propagating in a medium. What will be:
The ratio of their time period?