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Question

The ratio of van't Hoff factor for three different aqueous solutions of KCl,CuSO4 and CaF2 respectively is:
Assume 100% ionisation

A
1:1:1
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B
1:2:3
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C
2:2:3
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D
2:1:3
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Solution

The correct option is C 2:2:3
For 100% ionisation, van't Hoff factor is equal to the number of particles in which 1 ​molecule of electrolyte dissociates​.
KClK++Cl
iKCl=2
CuSO4Cu2++SO24
iCuSO4=2CaF2Ca2++2FiCaF2=3
iKCl:iCuSO4:iCaF22 : 2 : 3

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