The ratio of van't Hoff factor for three different aqueous solutions of KCl,CuSO4andCaF2 respectively is:
Assume 100% ionisation
A
1:1:1
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B
1:2:3
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C
2:2:3
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D
2:1:3
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Solution
The correct option is C2:2:3 For 100% ionisation, van't Hoff factor is equal to the number of particles in which 1 molecule of electrolyte dissociates. KCl→K++Cl− iKCl=2 CuSO4→Cu2++SO2−4 iCuSO4=2CaF2→Ca2++2F−iCaF2=3 iKCl:iCuSO4:iCaF22:2:3