The ratio of velocities of the diffusion of gases A and B is 1:4. If the ratio of their masses present in the mixture is 2:3, calculate the ratio of their mole fractions.
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Solution
rArB=√MBMA=14 or, MBMA=116
Let masses WA of A and WB of B be present respectively. So, WAWB=23 (given) Mole fraction ofA,χA=WAMAWAMA+WBMB Mole fraction ofB,χB=WBMBWAMA+WBMB χAχB=WAMA×MBWB or WAWB×MBMA=23×116=124