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Question

The ratio of volumes of 1 M KOH and 0.5 M H2SO4 solutions in a total volume of 100 ml, that produces the highest rise in temperature is:

A
67 : 33
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B
33 : 67
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C
40 : 60
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D
50 : 50
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Solution

The correct option is B 50 : 50
For maximum rise in temperature, complete neutralization of acid and bases takes place

so, N1V1=N2V2

or, n1M1V1=n2M2V2

let volume of KOH =x ml,

Therefore, volume of H2SO4=100x ml
we get,

1×1×x=2×0.5×(100x)

x=100x

x=50

volume of KOH =50 ml

volume of H2SO4=50 ml

Ratio of volumes =50:50

Option D is correct.

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