The ratio of weights of hydrogen and magnesium deposited by the same amount of electricity from aqueous $H_{2} S O_{4}$ and fused $M g S O_{4}$ are__________.

1 : 8

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1 : 12

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1 : 16

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none of these

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Solution

The correct option is D none of these
According to Faraday's Second Law,
$\frac{Weight of Hydrogen}{Weight of Magnesium} = \frac{Equivalent weight of H_{2} S O_{4}}{Equivalent weight of M g S O_{4}}$
Ratio= $\frac{\frac{98}{2}}{\frac{120}{2}} = \frac{49}{60} = \frac{7}{8.57}$
Since we know weight of $H_{2} S O_{4} = 98 g$
weight of $M g S O_{4} = 120 g$

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The ratio of weights of hydrogen and magnesium deposited by the same amount of electricity from aqueous H2SO4 and fused MgSO4 are__________.

The correct option is D none of theseAccording to Faraday's Second Law,Weight of HydrogenWeight of Magnesium=Equivalent weight of H2SO4Equivalent weight of MgSO4Ratio= 9821202=4960=78.57Since we know weight of H2SO4=98g weight of MgSO4=120g

The ratio of weights of hydrogen and magnesium deposited by the same amount of electricity from aqueous $H_{2} S O_{4}$ and fused $M g S O_{4}$ are__________.