The rational number lying exactly in between the numbers $\frac{1}{5}$ and $\frac{1}{3}$ is

\frac{1}{2}

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\frac{1}{4}

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\frac{2}{15}

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\frac{4}{15}

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\frac{8}{15}

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Solution

The correct option is D $\frac{4}{15}$
Required number $=$ $\frac{1}{2} (\frac{1}{5} + \frac{1}{3})$
$\Rightarrow \frac{1}{2} (\frac{3 + 5}{15})$
$\Rightarrow \frac{1}{2} \times \frac{8}{15} = \frac{4}{15}$
Hence, $\frac{4}{15}$ is a rational number lying between $\frac{1}{5}$ and $\frac{1}{3}$ .

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Similar questions

Add the following rational numbers :

(i) $\frac{- 2}{5}$ and $\frac{4}{5}$ (ii) $\frac{- 6}{11}$ and $\frac{- 4}{11}$ (iii) $\frac{- 11}{8}$ and $\frac{5}{8}$

(iv) $\frac{- 7}{3}$ and $\frac{1}{3}$ (v) $\frac{5}{6}$ and $\frac{- 1}{6}$ (iv) $\frac{- 17}{15}$ and $\frac{- 1}{15}$

Question 93 (d)

Find a rational number exactly halfway between
$\frac{1}{15} a n d \frac{1}{12}$

\frac{1}{5} + \frac{1}{- 6}, ∣ ∣ ∣ - \frac{7}{6} + 1 ∣ ∣ ∣, {(- \frac{1}{2})}^{3}, \frac{5}{8} \div \frac{- 15}{4}

\frac{- 3}{5}, \frac{- 6}{10}, \frac{- 9}{15}, \frac{- 12}{20}, . . .

\frac{- 1}{4}, \frac{- 2}{8}, \frac{- 3}{12}, . . .

The rational number which is not lying between $\frac{5}{16}$ and $\frac{1}{2}$ is
$(a) \frac{3}{8}$

$(b) \frac{7}{16}$

$(c) \frac{1}{4}$

$(d) \frac{13}{32}$

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