The rational number whose cube is 27125 -

The correct option is B 35 √(27125)=√( ( 3 )^3 ( 5 )^3)=35 ...

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Cube-Root of Fractional Numbers

The rational ...

Question

The rational number whose cube is $\frac{27}{125}$ :

\frac{3}{5}

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\frac{3}{15}

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\frac{2}{5}

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\frac{4}{5}

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Solution

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(2 - 8), (3 - 27), (4 - 32), (5 - 125)

72, \frac{5}{27}, \frac{62}{0}, 1 \frac{3}{5}, - 7 \frac{5}{4}, 0

\frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} - \sqrt{3}} = a + b \sqrt{15}

\frac{\sqrt{2} - \sqrt{3}}{3 \sqrt{2} - 2 \sqrt{3}} = a + b \sqrt{6}

\frac{4 - 3 \sqrt{5}}{4 - 3 \sqrt{5}} = a + b \sqrt{5}

Using commutativity and associativity of addition of rational numbers, express each of the following as a rational number:

(i) $\frac{2}{5} + \frac{7}{3} + \frac{- 4}{5} + \frac{- 1}{3}$

(ii) $\frac{3}{7} + \frac{- 4}{9} + \frac{- 11}{7} + \frac{7}{9}$

(iii) $\frac{2}{5} + \frac{8}{3} + \frac{- 11}{15} + \frac{4}{5} + \frac{- 2}{3}$

(iv) $\frac{4}{7} + 0 + \frac{- 8}{9} + \frac{- 13}{7} + \frac{17}{21}$

Write the following rational numbers in ascending order:

(i) (ii) (iii)

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