Question

The rationalizing factor of $\frac{5}{\sqrt[3]{33}}$ is.

• A. $\sqrt[3]{36}$
• B. $\sqrt[3]{33}$
• C. $\sqrt[3]{39}$
• D. $\sqrt[3]{327}$

Answer 1

Answer: (C)

$\sqrt[3]{39}$

Rationalizing factor is the factor with which numerator and denominator must be multiplied in order to get denominator rationalized.

Here, Denominator $=3^{\frac{1}{3}}$

$\therefore$ Rationalizing factor $=3^{1-\frac{1}{3}}=3^{\frac{2}{3}}=\sqrt[3]{39}$