The reactant which is entirely consumed in reaction is known as a limiting reagent. In the reaction $2 A + 4 B ⟶ 3 C + 4 D$ , $5$ moles of $A$ reacts with $6$ moles of $B$ , calculate the amount of $C$ formed.

4.5

moles

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2.5

moles

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6.5

moles

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5.5

moles

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Solution

The correct option is A $4.5$ moles
The balanced reaction is $2 A + 4 B \to 3 C + 4 D$ .
No. of moles given: $5$ $6$
Ratio of moles given and stoichiometry coefficient is:
$\frac{5}{2}$ $\frac{6}{4}$
As $1.5$ is lower than $2.5$ , $B$ is the limiting reagent and the product will form according to the number of moles of $B$ (given).
So, the moles produced of $C = \frac{3}{4} \times 6 = 4.5$ mol.

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Similar questions

The reactant which is entirely consumed in reaction is known as limiting reagent. In the reaction $2 A + 4 B \to 3 C + 4 D,$ when 5 moles of A react with 6 moles of B, then

(i) Which is the limiting reagent ?

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Q. The reactant which is entirely consumed in reaction is known as limiting reagent. In the reaction

2 A + 4 B ⟶ 3 C + 4 D

, if

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When 8 moles of x react with 15 moles of y, then
i) Which is the limiting reagent?
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The reactant which is entirely consumed in reaction is known as a limiting reagent. In the reaction 2A+4B⟶3C+4D, 5 moles of A reacts with 6 moles of B, calculate the amount of C formed.

The reactant which is entirely consumed in reaction is known as a limiting reagent. In the reaction $2 A + 4 B ⟶ 3 C + 4 D$ , $5$ moles of $A$ reacts with $6$ moles of $B$ , calculate the amount of $C$ formed.