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Molecular Speeds - Vrms, Vavg, Vmps

The reaction,...

Question

The reaction, $2 {S O}_{2} (g) + O_{2} (g) ⇌ 2 {S O}_{3} (g)$ is carried out in a 1 ${d m}^{3}$ vessel and 2 ${d m}^{3}$ vessel respectively. The ratio of the reaction velocities will be:

1 : 4

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2 : 4

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1 : 8

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8 : 1

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Solution

The correct option is D 8 : 1
The correct option is D
$R a t e (R)$ .proportional to $[S 0_{2}]^{2} [O_{2}]$
$R_{1}$ proportional to $[S o_{2}]^{2} [O_{2}]$
$R_{2}$ proportional to $[\frac{S o_{2}}{2}]^{2} [\frac{O_{2}}{2}]$
$\frac{R_{1}}{R_{2}} = \frac{[S o_{2}]^{2} [O_{2}]}{{\frac{[S o_{2}]}{4}}^{2} \frac{[O_{2}]}{2}}$
$\frac{R_{1}}{R_{2}} = \frac{8}{1}$
i.e $R_{1} : R_{2}$ = $8 : 1$

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