The reaction; 2A+B+C→D+2E; is found to be I order in A, II order in B and zero order in C. (a) Write the rate expression. (b) What is the effect on rate on increasing the conc. of A,B and C two times?
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Solution
(a) Rate=K[A]1[B]2[C]0
(b) Let initial conc. of A,B and C be a,b, and c mol litre−1 respectively
Then, Rate r1=Ka1b2c0
Now if conc. of A,B and C are doubled, i.e. 2a,2b and 2c respectively, then,