The reaction- 2A- B - Products- follows the mechanism- 2A - A2 at equilibrium A2 - B - Products slow The order of the reaction is-

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Standard XII

Chemistry

Rate of Reaction

The reaction,...

Question

The reaction, $2 A + B \to$ Products, follows the mechanism:

$2 A ⇋ A_{2}$ (at equilibrium)
$A_{2} + B \to$ Products (slow)

The order of the reaction is:

2

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1

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3

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1 \frac{1}{2}

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Solution

The correct option is C $3$
From the slow step, $r a t e = k [A_{2}] [B]$ ...... (1)
From the equilibrium reaction, equilibrium constant $K = \frac{[A_{2}]}{[A]^{2}}$
$[A_{2}] = K [A]^{2}$ ......(2)

Substitute equation (2) in equation (1).
$r a t e = k K [A]^{2} [B]$

Thus the overall order of the reaction is $2 + 1 = 3$ .

Hence, option C is correct.

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The reaction, 2A+B→ Products, follows the mechanism:2A⇋A2 (at equilibrium)A2+B→ Products (slow) The order of the reaction is:

The correct option is C 3From the slow step, rate=k[A2][B] ...... (1)From the equilibrium reaction, equilibrium constant K=[A2][A]2[A2]=K[A]2......(2)Substitute equation (2) in equation (1).rate=kK[A]2[B]Thus the overall order of the reaction is 2+1=3.Hence, option C is correct.

The reaction, $2 A + B \to$ Products, follows the mechanism:

$2 A ⇋ A_{2}$ (at equilibrium)
$A_{2} + B \to$ Products (slow)

The order of the reaction is: