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Rate of Reaction

The reaction,...

Question

The reaction,
$2 N O (g) + O_{2} (g) ⇋ 2 N O_{2} (g)$ is first order. If volume of reaction vessel is reduced to $\frac{1}{3},$ the rate of reaction would be :

\frac{1}{3}

times

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\frac{2}{3}

times

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3

times

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6

times

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Solution

The correct option is A $3$ times
For first-order reaction; rate law will be:

Rate of reaction $(R_{1}) = k [N O_{2}]$ ...(i)

If the volume of the reaction vessel is reduced to $\frac{1}{3},$ concentration increase by three times

Rate of reaction $(R_{2}) = k \times 3 [N O_{2}]$ ...(ii)

On dividing both equation:

$\frac{Rate of reaction (R_{1})}{Rate of reaction (R_{2})} = \frac{k [N O_{2}]}{k \times 3 [N O_{2}]}$

$R_{2} = 3 \times R_{1}$

Hence, the correct answer is option $C$ .

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Similar questions

2 N O_{(g)} + O_{2 (g)} \to 2 N O_{2 (g)}

k [N O]^{2} [O_{2}]^{1}

1 / 3^{r d}

_{(g)}

_{2 (g)}

\to

_{2 (g)}

[N O]^{2}

[O_{2}

^{1}

^{r d}

A (g) + B (g) \to 3 C (g)

r = k [A] {[B]}^{2}

\frac{1}{4}

2 N O + O_{2} \to 2 N O_{2}

= K {[N O]}^{2} [O_{2}]

{1 / 3}^{r d}

2 N O (g) + O_{2} (g) \to 2 {N O}_{2} (g)

= k {[N O]}^{2} [O_{2}]

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