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Question

 The reaction ; 2O33O2, is assigned the following mechanism.

(I) O3O2+O              (ii)O3+Oslow2O2

The rate law of the reaction will therefore be


  1. r α [O3]2[O2]

  2. r α [O3]2[O2]1

  3. r α [O3]

  4. r α [O3][O2]2


Solution

The correct option is B

r α [O3]2[O2]1


Clearly, step II is the Rate Determining Step. Hence the rate of overall reaction = Rate of Step II r=KII[O][O3]     ...(i)

For the equilibrium of Step I, we get:

Also for equilibrium, KC=[O][O2][O3]     ...(ii)

[O]=KC[O3][O2]   ...(iii)

Using (iii) in (i), we get:

r=KIIKC[O3][O3][O2]=K'[O3]2[O2]1

In other words r[O3]2[O2]1

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