Question

# The reaction ; 2O3 → 3O2, is assigned the following mechanism. (I) O3⇋O2+O              (ii)O3+Oslow⇌2O2 The rate law of the reaction will therefore be r α [O3]2[O2] r α [O3]2[O2]−1 r α [O3] r α [O3][O2]−2

Solution

## The correct option is B r α [O3]2[O2]−1 Clearly, step II is the Rate Determining Step. Hence the rate of overall reaction = Rate of Step II r=KII[O][O3]     ...(i) For the equilibrium of Step I, we get: Also for equilibrium, KC=[O][O2][O3]     ...(ii) ∴[O]=KC[O3][O2]   ...(iii) Using (iii) in (i), we get: ⇒r=KIIKC[O3][O3][O2]=K'[O3]2[O2]−1 In other words r∝[O3]2[O2]−1

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