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Synthesis of Aldehydes or Ketones from Hydrocarbons

The reaction ...

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The reaction 2o3----> 3o2 proceeds as follows o3 <====>o2+o (fast) o+o3 <====>2o2 (slow) the rate law expression for the reaction would be 1) r=k[o3]^2 2) r= k[o3]^2 [o2]^-1 3) r= k[o3] [o2] 4) r= [o2]^1

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Q. The chemical reaction,

2 O_{3} \to 3 O_{2}

proceeds as follows:

O_{3} ⇌ O_{2} + O

O + O_{3} \to 2 O_{2}

....(slow)

The rate law expression should be:

Q. The chemical reaction ,

2 O_{3} \to 3 O_{2}

proceeds as follows:

O_{3} ⇌ O_{2} + O

.......... (fast)
Step2:

O + O_{3} \to 2 O_{2}

............... (slow)

The rate law expression should be:

Q. The chemical reaction,

2 O_{3} \to 3 O_{2}

proceeds as follows;

O_{3} ⇌ O_{2} + O

O + O_{3} \to 2 O_{2}

....(Slow)
The rate law expression should be:

Q. The chemical reaction

{2 O}_{3} ⟶ {3 O}_{2}

proceeds as follows

O_{3} ⇌ O_{2} + O

O + O_{3} ⇌ {2 O}_{2}

......(slow)
The rate of expression should be

Q. For the chemical reaction,

2 O_{3} ⇌ 3 O_{2}

The reactions proceed as follows

O_{3} ⇌ O_{2} + O

O + O_{2} \to 2 O_{2}

(slow)
The rate law expression will be:

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