Question

The reaction 2o3----> 3o2 proceeds as follows o3 <====>o2+o (fast) o+o3 <====>2o2 (slow) the rate law expression for the reaction would be 1) r=k[o3]^2 2) r= k[o3]^2 [o2]^-1 3) r= k[o3] [o2] 4) r= [o2]^1

Answer 1