The reaction : $4 N_{2} O + C H_{4} \to C O_{2} + 2 H_{2} I + 4 N_{2}$ takes place in hte gaseous state. If all volumes are measured at the same temperature and pressure, calculate the volume of dinitrogen oxide $(N_{2} O)$ required to give $150 c m^{3}$ of steam.

$150 c m^{3}$

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$300 c m^{3}$

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$450 c m^{3}$

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$200 c m^{3}$

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Solution

The correct option is B
$300 c m^{3}$

$4 N_{2} O 4 V + C H_{4} 1 V \to C O_{2} 1 V + 2 H_{2} I 2 V + 4 N_{2} 4 V$

$2 \times 22400 c m^{3}$ steam produces $4 \times 22400 c m^{3} o f N_{2} O$

So $150 c m^{3}$ steam will produce $= 4 \times 22400 \times \frac{150}{2 \times 22400} = 300 c m^{3} o f N_{2} O$

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Similar questions

The reaction 4N₂O + CH₄ $\overset{}{\to}$ CO₂ + 2H₂O + 4N₂ takes place in the gaseous state. If the volumes of all the gases are measured at the same temperature, and pressure, calculate the volume of dinitrogen oxide (N₂O), required to give 150 cm³ of steam.

(b) The reaction: 4N₂O + CH₄ $\overset{}{\to}$ CO₂ + 2H₂O + 4N₂ takes place in the gaseous state. If all volumes are measured at the same temperature and pressure, calculate the volume of dinitrogen oxide (N₂O) required to give 150 cm³of steam.
(N = 14, O = 16, C = 12, H = 1)

4 N_{2} O + C H_{4} \to C O_{2} + 2 H_{2} O + 4 N_{2}

If all volumes are measured at the same temperature and pressure, the volume of

N_{2} O

required to give

150 c m^{3}

of steam is:

The reaction: takes place in the gaseous state. If all volumes are measured at the same temperature and pressure,

Calculate the volume of dinitrogen oxide (N₂O) required to give 150 cm³ of steam.

[N = 14,O = 16,C=12,H=1]

Q. Assuming that the all volume is measured at the same temperature and pressure, state the volume ratios of the reactants and products for the following gaseous reactions. Nitrogen reacting with oxygen to form nitrogen (III) oxide.

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The reaction : 4N2O+CH4→CO2+2H2I+4N2 takes place in hte gaseous state. If all volumes are measured at the same temperature and pressure, calculate the volume of dinitrogen oxide (N2O) required to give 150cm3 of steam.

The correct option is B 300 cm3 4N2O4V+CH41V→CO21V+2H2I2V+4N24V 2×22400 cm3 steam produces 4×22400 cm3 of N2O So 150 cm3 steam will produce =4×22400×1502×22400=300 cm3ofN2O

The reaction : $4 N_{2} O + C H_{4} \to C O_{2} + 2 H_{2} I + 4 N_{2}$ takes place in hte gaseous state. If all volumes are measured at the same temperature and pressure, calculate the volume of dinitrogen oxide $(N_{2} O)$ required to give $150 c m^{3}$ of steam.