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Nuclear Fission

The reaction,...

Question

The reaction, $_{92}^{235} U +_{0}^{1} n ⟶$ $_{56}^{140} B a +_{36}^{93} K r + 3$ represents:

artificial radioactivity

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nuclear fission

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nuclear fusion

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none of the above

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Solution

The correct option is B nuclear fission
The nuclei of some atoms decay by breaking into two smaller, more stable nuclei during a process called nuclear fission. The equation represents large atoms decaying into two or more.

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_{92}^{235} U +_{0}^{1} n \to 3_{0}^{1} n +_{56}^{139} B a +__________

_{92}^{235} U +_{0}^{1} n ⟶_{56}^{141} B a +_{36}^{92} K r + 3_{0}^{1} n + 200 M e V

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{}_{92}^{235}U + {}_{0}^{1}n \to_{}^{} {}_{56}^{139}{Ba} + {}_{36}^{94}{Kr} + x c + E

_{92}^{235} U +_{0}^{1} n \to_{56}^{139} B a +_{36}^{94} K r + 3_{0}^{1} n

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