Question

The reaction;

${}_{92}{U}^{238}+{}_0{n}^1\to {}_{92}{U}^{239}\to {}_{93}N{p}^{239}+{}_{-1}{e}^0$.
is an example of:

• A. $\alpha$-emission
• B. $\beta$-emission
• C. $\gamma$-emission
  
• D. none of these

Answer 1

The correct option is B $\beta$-emission

${}_{92}{U}^{238}+{}_0{n}^1\to {}_{92}{U}^{239}\to {}_{93}N{p}^{239}+{}_{-1}{e}^0$.

Neutron on collision with Uranium-238 forms Uranium-239 and then $\beta$- emission occurs to form Neptunium-239.