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Question

The reaction A(g)+2B(g)C(g)+D(g) is an elementary process. In an experiment , the initial partial pressure of A and B are PA=0.40 and PB=0.60atm. When PC=0.2atm and the rate of reaction relative to the initial rate is ?

A
1/48
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B
1/24
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C
9/16
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D
1/18
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Solution

The correct option is A 1/18

Initial partial pressure of A & B is 0.4 and 0.6 respectively
Rate law (initial) = k[0.4][0.6]2 ..............(1)

Now when P(c)=0.2 ........(let say x)
P(a)=0.4x=0.2
P(b)=0.62x=0.2

Therefore rate law(final) = k[0.2][0.2]2 ............(2)
divide eq2 and eq 1, = rate law(final)rate law(initial

=1\18


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